Two sources of sound placed close to each oth | vedclass

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(D) Given equations are $y_1 = 4 \sin(600\pi t)$ and $y_2 = 5 \sin(608\pi t)$.Comparing with $y = A \sin(2\pi 
u t)$,we get:For the first source: $A_

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$4$ beats per second with intensity ratio $81 : 1$ between waxing and waning.

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(D) Given equations are $y_1 = 4 \sin(600\pi t)$ and $y_2 = 5 \sin(608\pi t)$.Comparing with $y = A \sin(2\pi 
u t)$,we get:For the first source: $A_1 = 4$ and $2\pi 
u_1 = 600\pi \implies 
u_1 = 300 	ext{ Hz}$.For the second source: $A_2 = 5$ and $2\pi 
u_2 = 608\pi \implies 
u_2 = 304 	ext{ Hz}$.The number of beats heard per second is the difference in frequencies: $	ext{Beat frequency} = 
u_2 - 
u_1 = 304 - 300 = 4 	ext{ beats/sec}$.The ratio of maximum intensity to minimum intensity is given by $\frac{I_{\max}}{I_{\min}} = \frac{(A_1 + A_2)^2}{(A_1 - A_2)^2}$.Substituting the values: $\frac{I_{\max}}{I_{\min}} = \frac{(4 + 5)^2}{(4 - 5)^2} = \frac{9^2}{(-1)^2} = \frac{81}{1}$.Thus,the observer hears $4$ beats per second with an intensity ratio of $81 : 1$.

Two sources of sound placed close to each other are emitting progressive waves given by $y_1 = 4 \sin(600\pi t)$ and $y_2 = 5 \sin(608\pi t)$. An observer located near these two sources of sound will hear:

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